> then there are 10^100 possible paths through that session.
Is this correct? in practice you would only be deciding what the next turn is going to be. Because the turn after the next turn is determined by the outcome of the next turn. So shouldn't this number be 10 * 100?
paths friend. so first turn you have ten options, second u have the same ten. assume turn one model h1. turn two you have ten options. 1x10. but you could have chosen any h on the first turn. so 10x10=100. turn three you could have gotten there 100 ways and still have ten options.
My calculation exactly!