I don't understand your problem. Did you expect your C++ program to get uninterrupted access to the computer? What progression do you think isn't happening there?
I think you are misinterpreting that. That phrase unambiguously says the loop is preserved on the final binary.
I expect an infinite loop to be compiled into, for instance, a jump instruction jumping to itself. The OS, if there is any, is welcome to interrupt and context switch. I don't expect code that has no function calls at all to have a system call inserted into it.
A call to a standard library function is still subject to the as if rule. It doesn't have to manifest into a call instruction to a standard library function. Much like memcpy in source code doesn't have to manifest to a call instruction.
Yes, but the compiler does have to preserve any observable behavior produced by the call to the standard library function. Being able to omit this inserted yield() by the as if rule would mean that it isn't observable, which would also mean that the compiler could already add or not add it anywhere as needed without changing the behavior of the program. Which would seemingly make the inserted yield() pointless as it would have no effect.
Me: I don't expect to be stabbed.
You: But you only might be stabbed. It isn't required to happen only permitted.
Ok, I get this.
The problem is that what you want is completely against the spirit of the entire language.
If your point is that C++ should be more like C in general, I can agree with that. But if your point is that C++ should be literal on this specific case, performance be damned, and the rest of it is ok, then no, that's a bad one.
I was utterly unconvinced that the original infinite-loop UB gave the compiler any important performance optimization, and I'm unconvinced that this is providing useful value to compensate for its surprise. If I wanted a yield in my infinite loop, I'd add one.
The original UB was to allow the compiler to merge two loops without proving termination.
What difference does it make? If the loop doesn't terminate, it doesn't terminate, which is almost always a bug, except when it's not. If it does terminate, then great, it terminates.
Merging a buggy loop with another loop creates... a buggy loop.
Take this example:
It can be conveniently transformed into this: They are exactly equivalent except if the first loop never terminates.Now, the compiler could try to understand if the first loop does or doesn't terminate, and apply or not the optimization accordingly, but Turing tought us that is indeed a hard task!
Or it could decide to never apply it, for fear of those rare and usually pathological cases where the first loop doesn't terminate.
Or it could decide to apply it by default and accept that in those cases the program does something different than what the source code says. The latter is better known as UB.
The third option won, and that's why infinite loops are UB in the standard.
Any program in an OS only gets as much resources allocated to it as the OS allows (OK, in any general-purpose OS written in the past few decades). sched_yield() doesn't actually reduce that allocation in most cases, anyhow: in fact it has a higher chance of increasing the resources that the thread uses spinning in a loop because it's gonna be thrashing the scheduler as well.