> The blue car, using ½mv², shed (~70²=) 4900 units of energy (we'll hand wave away the constants). So the red car, which had (100²=) 10000 units of kinetic energy to start, also shed 4900 units, which means it had 5100 units of energy when it collided, and so was going (√5100~) 71
But if the cars produce downforce this is no longer true because you brake harder (more friction available) at higher speeds!
This is how F1 cars pull 4G when breaking. Some custom cars (like one of Ken Block’s last monsters or the Valkyre) use active aero braking to even greater effect.
1. +1 insightful, thanks for sharing your physics knowledge
2. I know you know this, but for the sake of others, it's when _braking_ (applying the brakes), not _breaking_ (becoming broken).
I'm not a pedant. But these errors jump out at me and I'm always a bit surprised and dismayed at this dichotomy; in our field, somehow the requisite attention to detail, the precision inherent to communicating scientific concepts, code, algorithms and formulae, is so often just abandoned when it comes to prose.
> the precision inherent to communicating scientific concept /./ abandoned when it comes to prose.
Honestly that was a typo and I noticed too late to edit. Thanks for catching
Brake or break? Both are correct: if you don't do one you do the other.
But what if the cars are spherical cows?
I'm sorry to inform you that those cows are going to have a hard time braking on that frictionless surface.
Based on a hike in the Carson National Forest 2 days ago, the only reason a cow is on a frictionless surface is that the cow shat all over it.
Cows can't roll that fast.
Spherical cows on the other hand have to move with orbital velocity at least, or they fail to stay in vacuum for long and splash.
Not with that attitude
It takes a stupid cow, but when they can climb mountains as they do it is not inconcievable that one can roll down.
(I was suprised to see a cow jumping up on a ~3m rock ledge like it was nothing)
However, they can go up stairs, but not down them.
Or on shabbos
While it is true that some cars can brake harder due to downforce etc, the point from GP was that both cars brake/ decelerate at the same rate. Regardless of how exactly that deceleration is achieved.
> the point from GP was that both cars brake/ decelerate at the same rate
Point is that’s not always true. If they are the same type of car, and the car happens to be the kind with downforce, then their rate of deceleration greatly depends on air speed. A downforce car decelerates faster at higher speeds.
This is why you often see race cars lock their wheels towards the end of the braking zone, never at the beginning. The driver has to release the brakes as the car decelerates because there’s less friction available. You go from pulling 4G at the beginning of the braking zone to pulling the usual 1G once your speed drops enough for downforce to become negligible.
Alos! Many non-race cars actualy produce lift. Meaning the faster car decelerates at a slower rate than the slower car (0.8G vs 1G), making the effect from OP even more pronounced.
> This is why you often see race cars lock their wheels towards the end of the braking zone, never at the beginning.
That’s not the only reason, and I’m not even sure it’s the majority reason.
Braking in a straight line offers more braking traction than braking while turning. What happens towards the end of a braking zone? The turn in. (Which also shifts weight to the outside tire and away from the inside tire.)