> so 6/7=[2,4,14,28]. Whether this is optimal or not is open to argument. It's longer than [2,3,42], but on the other hand the denominators are smaller.
Also 6/7 = [2,7,7,14]
> so 6/7=[2,4,14,28]. Whether this is optimal or not is open to argument. It's longer than [2,3,42], but on the other hand the denominators are smaller.
Also 6/7 = [2,7,7,14]
That's not an Egyptian fraction decomposition because there are 2 sevens.