Look at it (2.5 t/h) by volume (0.82 kg/L): 3 kL/h (790 gal/h) == 50 L/m (13 gal/m) == 830 mL/s (0.9 qt/s), and then divide the total flow rate by 2 for rate per engine.

Or divide the total by the number of passengers (~189) flying to consider effective fuel economy (per passenger) or 13 kg/pax/h or 3.6 g/pax/s.

They must plan to never land with less than 30 minutes of fuel, or about 1.25 t, and I'd say they should never, ever land with less than 15 minutes in their career during a pan/mayday bingo fuel emergency.