A black hole.

A black hole is no more a perfect sphere than a sun is. Would gravity from the nearest other black hole not have a deforming effect of at least 2^-64 ?

A non-rotating black hole. Or a rotating black hole with zero charge. Or a rotating black hole with non-zero charge no external magnetic fields. Or a rotating black hole with non-zero charge with non-time-varying external magnetic fields. Or a wart on a frog on a bump on the log on a hole on the bottom of the sea.

There is no black hole that is a perfect sphere. That would, at a minimum, require a body with absolutely no angular momentum which isn't in anyway feasible.

Any rotating/spinning black hole will no longer be a perfect sphere.

Yeah but if you look down the axis of rotation you will have a perfect (to many decimal places anyways) circle... which was the demand.

That might be right.

But even then, the biggest black hole we think is possible measured down to the planck length gives you a number with 50 digits. And the entire observable universe measured in planck lengths is about 60 digits.

So how are you going to get a physical pi of even a hundred digits on the path toward arbitrary precision?

> to many decimal places anyway

> > The idea of arbitrary precision is intrinsically broken in physical reality.

There is no contradiction here.

Yeah I was just responding to the 64bit float thing, people overestimate floats.