Sorry, if there are N clients, and M servers, then there are N+M endpoints, but N*M links, which is a lot more.
The link is only as strong as it's weakest... link? Anyway, given the structure of internet, I wouldn't say it is O(N*M), more like O(the number of major ISPs).
Well all endpoints might differ but the links might rely on the exact same algorithm so you need to count distinct links
The link is only as strong as it's weakest... link? Anyway, given the structure of internet, I wouldn't say it is O(N*M), more like O(the number of major ISPs).
Well all endpoints might differ but the links might rely on the exact same algorithm so you need to count distinct links